Question

Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part A sliding door with weight F= 300 lb is mounted on a horizontal rail as shown in the figure. The coefficients of static friction between the rail and the door at A and Bare 0.15 and 0.25, respectively -5fB N 6 ft Determine the horizontal force that must be applied to the handle in order to move the door to the right. The horizontal force that must be applied to the handle is Ib(Click to select)

Answer 1

The horizontal force that must be applied to the handle in order to move the door to the right is 75 lb.

To determine the horizontal force that must be applied to the handle in order to move the door to the right, we need to consider the forces acting on the door. The weight of the door, F, is 300 lb. We also have the coefficients of static friction between the rail and the door at A and B, which are 0.15 and 0.25, respectively.

First, let's calculate the force of static friction at point A. This can be done by multiplying the coefficient of static friction by the weight of the door.

`F_(friction)_A = \mu A * F = 0.15 * 300 lb = 45 lb`

Next, let's calculate the force of static friction at point B.

`F_(friction)_B = \mu B * F = 0.25 * 300 lb = 75 lb`

To move the door to the right, we need to overcome the force of static friction at point B. Therefore, the horizontal force that must be applied to the handle is 75 lb.