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How many grams of NaOH are required to prepare 800.0 mL of 4.0MNaOH solution? A. 12 g B. 39 g C. 24 g D. 1.3×10^2 g E. 3.2×10^2 g

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The correct option is D. 1.3×10² gExplanation:We know that: The molar mass of NaOH (sodium hydroxide) is 40 g/mol.A 4.0 M solution contains 4.0 mol of NaOH in 1.0 L of solution.Here, we have 800.0 mL of 4.0 M NaOH solution, which means 0.8 L.Using the formula for calculating the mass of a substance given its molarity and volume, we have:Number of moles of NaOH in the solution = Molarity × Volume in liters = 4.0 mol/L × 0.8 L = 3.2 molUsing the molar mass of NaOH, we can calculate the mass of 3.2 moles of NaOH:Mass = Number of moles × Molar mass = 3.2 mol × 40 g/mol = 128 g≈ 1.3×10² gTherefore, we require 1.3×10² g of NaOH to prepare 800.0 mL of 4.0M NaOH solution.

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