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3 votes
Dave's Taxi

C = 1.8x
Pete's Cab
C = 1.5x + 5
Rick's
Rickshaw
C=1.9x-3.5
Jenny wants to get a lift to the Airport.
The distance to the Airport is 20 miles
C is the cost of the trip when x = the number of miles.
Jenny has £40.
How much change would she have if she took the cheapest service?

User ArBro
by
8.5k points

1 Answer

3 votes

We know that 20 miles is the distance to tbe airport. So, we should start by substituting the x on each expression with 20.

This way we can find the cost of each ride.

Dave

C=1.8x

C=1.8(20)

C=36

Dave's ride would cost 36 pounds .

Pete

C=1.5x+5

C=1.5(20)+5

C= 30+5

C=35

Pete's ride would cost 35 pounds.

Rick

C=1.9x-3.5

C=1.9(20)-3.5

C=38-3.5

C=34.5

Rick's ride would cost 34.5 pounds.

The cheapest ride would be Rick's Rickshaw.

Now, we just figure out the change .

Jenny has 40 pounds

So, subtracting with the cheapest rate of 34.5:

40-34.5=5.5

Answer. Jenny would get 5.5 pounds in change if she took the cheapest ride.

User Tek
by
8.1k points