Answer:
The given quadratic function has two real zeros, which means that its graph intersects the x-axis at two distinct points. To change it to a function with one real zero, we need to shift the graph vertically so that it intersects the x-axis at only one point.
Since the vertex of the given function is at (-3, -3), we can shift the graph downward by 3 units by subtracting 3 from the right side of the equation. This gives us:
y = 2(x + 3)² - 6
The graph of this function is still a parabola that opens upward, but it is shifted downward by 3 units. The new vertex is at (-3, -6), and the graph intersects the x-axis at only one point, which means that the function has one real zero.