Question

Mike is 12 years old and his father is 38 years. In how many years will the father be twice as old as Mike​

Answer 1

John present age = J, and Son present age = 12
after a specific number of years defined as X in general, John wil be twice as old as his son.
so at that time (X number of years into the future from present),
J+X = 2 × (S + X) ... (1)

Answer 2

14 years

Explanation:

Let's assume the number of years from now when the father will be twice as old as Mike is represented by "x".

Currently, Mike is 12 years old, and his father is 38 years old. After "x" years:

Mike's age: 12 + x

Father's age: 38 + x

According to the given condition, the father's age will be twice as old as Mike's age. Therefore, we can write the equation:

38 + x = 2(12 + x)

Let's solve this equation to find the value of "x":

38 + x = 24 + 2x

Subtracting x from both sides:

38 = 24 + x

Subtracting 24 from both sides:

14 = x

Therefore, in 14 years, the father will be twice as old as Mike.