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The angle of a quadrilateral are 3x°,(2x+5),(3x-10) and (2x+15)° find the value of x and hence the value of the angles ​

User Kubie
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1 Answer

1 vote

Step-by-step Step-by-step explanation:

Let's assume that:

Angle A = 3x

Angle B = (2x + 5)

Angle C = (3x - 10)

Angle D = 2x + 15

Sum of all four angles of quadrilateral = 360°

3x + 2x + 5 + 3x - 10 + 2x + 15 = 360

5x + 5 + 3x - 10 + 2x + 15 = 360

10x + 5 - 10 + 15 = 360

10x -5 + 15 = 360

10x + 10 = 360

10x = 360 - 10

10x = 350

x = 350/10

x = 35°

Now substitute the value of x = 35 in all the angles:

Angle A = 3x = 3(35) = 105°

Angle B = (2x + 5)

= 2(35) + 5 = 70 + 5 = 75°

Angle C = (3x - 10)

= 3(35) - 10 = 105 - 10 = 95°

Angle D = 2x + 15

= 2(35) + 15 = 70 + 15 = 85°

The angles are the quadrilateral are 105°, 75°, 95° and 85°

User Yoah
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