Question

A 71.5N force, acting on a crate at an angle of 27°, pulling it on a frictionless floor. If the crate is moved 5.50m, calculate the work done by the force.

Answer 1

The answer is approximately 350.4J to 1d.p

Step-by-step explanation:

W=F×S

F=F cosø

W=Fcosø×S

W=71.5cos27×5.5

W=63.7×5.5

W=350.35J

W≈350.4J