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A 71.5N force, acting on a crate at an angle of 27°, pulling it on a frictionless floor. If the crate is moved 5.50m, calculate the work done by the force.

1 Answer

3 votes

Answer:

The answer is approximately 350.4J to 1d.p

Step-by-step explanation:

W=F×S

F=F cosø

W=Fcosø×S

W=71.5cos27×5.5

W=63.7×5.5

W=350.35J

W≈350.4J

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