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Write the following quadratic expression in standard form (2x-1)(3x-1)

User Crowjonah
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2 Answers

3 votes

Answer:

6X^2-5X+1

Explanation:

User Drewster
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4 votes

Answer:

Standard form = 6x^2 - 5x + 1

Explanation:

Currently, (2x - 1)(3x - 1) is in factored, whose general equation is given by:

f(x) = a(x - r)(x - s), where

  • a is a constant determining if the parabola opens up or down,
  • and r and s are the factors.

The general equation of the standard form is given by:

f(x) = ax^2 + bx + c.

Thus, we can convert from factored to standard form using the FOIL method where:

  • F refers to the first terms (2x and 3x),
  • O refers to the outer terms (2x and -1),
  • I refers to the inner terms (-1 and 3x),
  • and L refers to the last terms (-1 and -1).

We multiply the first, outer, inner, and last terms and simplify at the end:

(2x * 3x) + (2x * -1) + (-1 * 3x) + (-1 * -1)

6x^2 - 2x - 3x + 1

6x^2 - 5x + 1

Thus, the standard form of the quadratic expression (2x - 1)(3x - 1) is 6x^2 - 5x + 1.

User Gusto
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