212k views
4 votes
The perimeter of the rectangle below is 100 units. Find the length of side XY.

Write your answer without variables.

(if you have the other answers from this lesson, pls let me know)

The perimeter of the rectangle below is 100 units. Find the length of side XY. Write-example-1

1 Answer

6 votes

Answer:

XY = 30 units

Explanation:

The formula for the perimeter of a rectangle is given by:

P = 2l + 2w, where

  • P is the perimeter,
  • l is the length,
  • and w is the width.

Since the opposite sides of rectangles are equal, WV = XY and VY = WX.

Thus, the length of side XY is also 3y + 3, and the length of side WX is also 2y + 2.

Note that sides VY and WX represent the width of the rectangle while sides WV and XY represent the length of the rectangle.

Step 1: Find y:

Before we can find the length of side XY, we'll first need to know the value of the variable y in 3y + 3 and 2y + 2.

We can find y by plugging in 3y + 3 for l and 2y + 2 for w, and 100 for P in the perimeter formula:

100 = 2(3y + 3) + 2(2y + 2)

100 = (2 * 3y) + (2 * 3) + (2 * 2y) + (2 * 2)

100 = (6y + 4y) + (6 + 4)

(100 = 10y + 10) - 10

(90 = 10y) / 10

9 = y

Thus, y = 9.

Step 2: Find the length of side XY:

Now we can find the length of side XY by plugging in 9 for y in 3y + 3 and simplifying:

XY = 3(9) + 3

XY = 27 + 3

XY = 30

Thus, the length of side XY is 30 units.

User Islingre
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.