Geometry Answer fast

Question

asked Oct 15, 2024 122k views

2 Answers

Gregoltsov · Answer 1 · 2024-10-18T21:03:18+0000

Answer:

5 units.

Explanation:

Given:

$\tt A(x_1,y_1)=(-3,-3)\\D(x_2,y_2)=(0,1)$

The distance from point A to line BC, at point D is calculated by using the formula:

distane=
$\tt √((x_2-x_1)^2+(y_2-y_1)^2)$

substituting value

distance=
$\tt √((0-(-3))^2+(1-(-3))^2)$

distance =
$\tt √(3^2+4^2)$

distance =
$\tt √(25)$

distance = 5

Therefore, the distance from point A to line BC, at point D is 5 units.