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What is the equation of the line that passes through the points (−3, −5) and (2, −3)?

User Greenify
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Answer:

Explanation:

To find the equation of a line that passes through two given points, we can use the point-slope form of a linear equation.

Let's denote the coordinates of the first point as (x1, y1) and the coordinates of the second point as (x2, y2):

First point: (-3, -5)

Second point: (2, -3)

We can calculate the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Substituting the coordinates into the formula:

m = (-3 - (-5)) / (2 - (-3))

m = (-3 + 5) / (2 + 3)

m = 2 / 5

Now that we have the slope (m), we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

Choosing either of the given points, let's use the first point (-3, -5):

y - (-5) = (2/5)(x - (-3))

y + 5 = (2/5)(x + 3)

Simplifying the equation:

y + 5 = (2/5)x + 6/5

y = (2/5)x + 6/5 - 5

y = (2/5)x + 6/5 - 25/5

y = (2/5)x - 19/5

Therefore, the equation of the line that passes through the points (-3, -5) and (2, -3) is y = (2/5)x - 19/5.

User HighFlyingFantasy
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