Question

PLEASE HELP ASAP, What is the equation of the line in slope-intercept form that passes through the point (−1, −3) and has a slope of 4?

Answer 1

The answer is:

y = 4x + 1

Work/explanation:

I will begin by writing the equation in point slope form, which is:

`\sf{y-y_1=m(x-x_1)}`

where m = slope, and (x₁,y₁) is a point

Plug in the data from the problem

`\begin{gathered}\bf{y-(-3)=4(x-(-1)}\\\bf{y+3=4(x+1)}\\\bf{y+3=4x+4}\\\bf{y=4x+4-3}\\\bf{y=4x+1}\end{gathered}`

Hence, the equation is y = 4x + 1.

Answer 2

Answer: y = 4x + 1

Explanation:

First, we will create a point-slope equation.

Given:

y - y1 = m(x - x1)

Distribute:

y - - 3 = 4(x - - 1)

Combine two negatives into a positive:

y + 3 = 4(x + 1)

Distribute the 4:

y + 3 = 4x + 4

Subtract 3 from both sides of the equation:

y = 4x + 1