Answer:
Explanation:
The graph of f(x) = 3 (4)2-5 + is a vertical stretch of the parent function f(x) = 42-5. So the answer is A.
The parent function f(x) = 42-5 is a parabola that opens upwards and has its vertex at (0, -5). The graph of f(x) = 3 (4)2-5 + is also a parabola that opens upwards, but it is taller than the parent function. This is because the factor of 3 in front of the function stretches the parabola vertically by a factor of 3.
The graph of f(x) = 3 (4)2-5 + is also translated upwards by 5 units, since the constant term +5 is added to the function. This means that the vertex of the graph is shifted 5 units upwards, to the point (0, 0).