Question

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What is the Standard Form of the line with x-intercept of 6 and y-intercept of 2?
please help

Answer 1

2 Answers By Expert Tutors

If the y intercept is 2 our line will have an equation of the form y=Ax+2. Since we need the x intercept to be 6 we have that 0=6A+2 or A=-1/3. Thus, the equation is y=-(1/3)x+2. I hope it helps

Answer 2

x + 3y = 6

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (0, 2 ) , y- intercept and (x₂, y₂ ) = (6, 0), x- intercept

m =
`(0-2)/(6-0)` =
`(-2)/(6)` = -
`(1)/(3)`

given the y- intercept is 2 , then c = 2

y = -
`(1)/(3)` x + 2 ← equation in slope- intercept form

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers ) , then

multiply the equation through by 3 to clear the fraction

3y = - x + 6 ( add x to both sides )

x + 3y = 6 ← equation in standard form