Question

2 A right cylinder with a base that has a radius of 6 inches is shown below. Its volume is 396m.

V=лr²h
What is the height, in feet, of the cylinder? Round to the nearest tenth.
Show your work.

Answer 1

• 11.48 feet

Explanation:

As per the given statement -

A right cylinder with ,

• Radius of base = 6 inches
• Volume = 396

Volume of the cylinder can be calculated as :

• V = πr²h

here

• r denotes radius
• h denotes height
• π = 3.14

Plugging the values in the above formula

`396 = 3.14 * (6)^2 * h \\ \\ 396 = 3.14 * 36 * h \\ \\ 396 = 113.06 * h \\ \\ h = (396)/(113.06 ) \\ \\ { \pink{{ \boxed{h \approx 3.5 \: m}}}}`

In feet,

1 metre = 3.2808 feet

3.5 metre = 3.2808 ft × 3.5

= 11.48 feet (approximately)

Hence, The the height, in feet, of the cylinder is 11.48 feet