Question

he angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60 degree. find the height of the building. round your answer to the nearest tenth.

Answer 1

The figure is not shown--please sketch it to confirm my answer.

In a 30°-60°-90° right triangle, the length of the longer leg is √3 times the length of the shorter leg. So the height of the building is 50√3 m, or about 86.60 m.