Question

a car accelerates along a straight line from rest to a final velocity of 55 ft/s in 4 seconds. what is the magnitude of the car's acceleration?

Answer 1

We are given the initial velocity (v0) is 0 ft/s, the final velocity (v) is 55 ft/s, and the time (t) is 4 seconds.

We want to find the acceleration (a). The equation relating these variables is:

v = v0 + at

Plugging in the known values:

55 = 0 + a(4)

55 = 4a

Divide both sides by 4:

55/4 = a

Therefore, the magnitude of the car's acceleration is:

a = 13.75 ft/s2

So in summary, the car's acceleration is:

a = 13.75 ft/s2

The key here is using the acceleration equation:

v = v0 + at

Answer 2

Ans=13.75

Step-by-step explanation:

a=v-u

t

a= 55-0

4

a=13.75m/s^2