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Graph the line passing through (−5,−4) whose slope is m=1/5.

User Kibwe
by
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2 Answers

7 votes

The answer is:

below

Work/explanation:

First, we need to find the equation of the line. We're given that:

its slope = 1/5

a point it goes through = (−5,−4)

Plug the data into point-slope


\rm{y-y_1=m(x-x_1)}

where m = slope and the point is (x₁, y₁).

Plug in:


\rm{y-(-4)=(1)/(5)(x-(-5)}

Simplify fully


\rm{y+4=(1)/(5)(x+5)}

Now let's graph it. I'll use Desmos - the graphing calculator.

Graph the line passing through (−5,−4) whose slope is m=1/5.-example-1
User Kjprice
by
8.0k points
4 votes

Answer:


y=(1)/(5)x-3

Explanation:


y-y_1=m(x-x_1)\\y-(-4)=(1)/(5)(x-(-5))\\y+4=(1)/(5)(x+5)\\y+4=(1)/(5)x+1\\y=(1)/(5)x-3

Plot that into Desmos and you got your graph :)

User DaveA
by
8.0k points

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