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the basicity of tetraoxosulphate vi acid is 2 explain this statement with an equation showing the reaction between the acid and potassium hydroxide

User Singrium
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Final answer:

The basicity of tetraoxosulphate VI acid is 2 because it has two replaceable hydrogen atoms. When reacting with potassium hydroxide (KOH), two hydroxide ions (OH-) are needed to neutralize the two hydrogen atoms in the acid and form water (H2O). The remaining ions, K+ and SO42-, form the salt potassium sulfate (K2SO4).

Step-by-step explanation:

The basicity of tetraoxosulphate VI acid is 2 because it has two replaceable hydrogen atoms. When reacting with potassium hydroxide (KOH), two hydroxide ions (OH-) are needed to neutralize the two hydrogen atoms in the acid and form water (H2O). The remaining ions, K+ and SO42-, form the salt potassium sulfate (K2SO4). The balanced chemical equation for this reaction is:

H2SO4 + 2KOH → K2SO4 + 2H2O

User Piezol
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