Final answer:
The basicity of tetraoxosulphate VI acid is 2 because it has two replaceable hydrogen atoms. When reacting with potassium hydroxide (KOH), two hydroxide ions (OH-) are needed to neutralize the two hydrogen atoms in the acid and form water (H2O). The remaining ions, K+ and SO42-, form the salt potassium sulfate (K2SO4).
Step-by-step explanation:
The basicity of tetraoxosulphate VI acid is 2 because it has two replaceable hydrogen atoms. When reacting with potassium hydroxide (KOH), two hydroxide ions (OH-) are needed to neutralize the two hydrogen atoms in the acid and form water (H2O). The remaining ions, K+ and SO42-, form the salt potassium sulfate (K2SO4). The balanced chemical equation for this reaction is:
H2SO4 + 2KOH → K2SO4 + 2H2O