Question

6.25 mL of an unknown gas has its pressure decreased from 1.09 atm to 0.6 atm. Assuming temperature remains constant, what would be the final volume of the unknown gas?

Round your answer to the nearest hundredth.

Answer 1

The final volume of the unknown gas, when the pressure is decreased from 1.09 atm to 0.6 atm at constant temperature, is 11.35 mL.

Step-by-step explanation:

The final volume of the unknown gas can be calculated using Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. We can use the equation:

P1 * V1 = P2 * V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Using the given information, P1 = 1.09 atm, V1 = 6.25 mL, and P2 = 0.6 atm.

Plugging these values into the equation, we get:

(1.09 atm) * (6.25 mL) = (0.6 atm) * (V2)

Solving for V2:

V2 = (1.09 atm * 6.25 mL) / (0.6 atm) = 11.35 mL

Rounding to the nearest hundredth, the final volume of the unknown gas would be 11.35 mL.

Answer 2

Using Boyle's Law, the final volume of an unknown gas with an initial volume of 6.25 mL and pressure decreased from 1.09 atm to 0.6 atm is found to be 11.25 mL, assuming constant temperature.

Step-by-step explanation:

The question concerns the relationship between pressure and volume of a gas, which is described by Boyle's Law. Boyle's Law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume when the temperature and amount of gas are kept constant. In mathematical terms, P1•V1 = P2•V2. Using this law, we can calculate the final volume (V2) of the gas when the pressure changes.

Given the initial conditions of an unknown gas having a volume of 6.25 mL (V1) at a pressure of 1.09 atm (P1) and the final pressure being 0.6 atm (P2), we can rearrange Boyle's Law to solve for V2: V2 = (P1•V1) / P2.

Substituting the known values into the equation gives us V2 = (1.09 atm • 6.25 mL) / 0.6 atm, which simplifies to V2 = 11.25 mL. Therefore, the final volume of the unknown gas when the pressure is decreased to 0.6 atm while maintaining constant temperature is 11.25 mL.