Question

Hi school students across the nation compete in a financial compatibility challenge each year by taking in national financial compatibility challenge exam students whose score in the top 5% or recognized publicly for their achievement by the department of treasury assuming a normal distribution how many standard deviation above the mean does a student have to score to be publicly, recognized (round your answer to 2 decimal place )

Answer 1

To determine how many standard deviations above the mean a student has to score to be publicly recognized, we need to calculate the z-score. The z-score measures the number of standard deviations a data point is from the mean in a normal distribution.

In this case, the top 5% of students are recognized publicly for their achievements. Since the normal distribution is symmetrical, we can find the z-score corresponding to the top 5% and determine how many standard deviations it is from the mean.

The area under the standard distribution curve for the top 5% is 0.05. To find the z-score, we can use a standard normal distribution table or a statistical calculator.

The z-score corresponding to an area of 0.05 is approximately 1.645. Therefore, a student must score approximately 1.645 standard deviations above the mean to be publicly recognized.

Rounded to two decimal places, the answer is 1.65 standard deviations above the mean.

I hope this helps! J'espère que ça aide! ich hoffe das hilft!