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Write an exponential function in the form y=ab that goes through the points (0,3) and (2,243)

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Answer:

y = 3 * 9^x

Explanation:

To write an exponential function in the form y = ab that goes through the points (0, 3) and (2, 243), we need to find the values of a and b.

Let's start by using the point (0, 3). When x = 0, y = 3. Substituting these values into the exponential function equation, we get:

3 = ab^0

3 = a * 1

a = 3

Now, let's use the second point (2, 243). When x = 2, y = 243. Substituting these values into the exponential function equation, we get:

243 = 3b^2

To find the value of b, we can rewrite the equation as:

3b^2 = 243

Dividing both sides of the equation by 3, we have:

b^2 = 81

Taking the square root of both sides, we get:

b = ±9

Since we are looking for a positive value for b, we can take b = 9.

Therefore, the exponential function that goes through the points (0, 3) and (2, 243) is: y = 3 * 9^x

User Tobias Wichtrey
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