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How do I determine if the ordered pair (2x-y=1 and 5x-3y=1) is a solution of the given system of equations?

User Burning
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Answer: To determine if the ordered pair (x, y) is a solution of the given system of equations, you need to substitute the values of x and y into each equation and check if both equations hold true.

Given system of equations:

2x - y = 1

5x - 3y = 1

Let's substitute the values of x and y from the ordered pair (x, y) into each equation:

For equation 1:

2x - y = 1

Substituting x = 2 and y = -1:

2(2) - (-1) = 4 + 1 = 5

For equation 2:

5x - 3y = 1

Substituting x = 2 and y = -1:

5(2) - 3(-1) = 10 + 3 = 13

Now, compare the results of each equation with the right-hand side of the respective equation:

For equation 1: 5 (left side) ≠ 1 (right side)

For equation 2: 13 (left side) ≠ 1 (right side)

Since both equations do not hold true when substituting the values of x = 2 and y = -1, the ordered pair (2, -1) is not a solution of the given system of equations.

Step-by-step explanation: Hope this helps!

User Arjun Panicker
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