Question

When a metal was exposed to photons at a frequency of 1.05×1015 s−1, electrons were emitted with a maximum kinetic energy of 3.80×10−19 J.

Answer 1

The question relates to the photoelectric effect and how the frequency of light affects the kinetic energy of emitted electrons. Einstein's theory of photons provides an explanation for this phenomenon.

Step-by-step explanation:

The question is related to the photoelectric effect, which is a phenomenon in which electrons are ejected from a metal's surface when exposed to light. The number of emitted electrons and their kinetic energy depend on the frequency and intensity of the light, respectively. This contradicted the predictions of classical physics, but Einstein's idea of photons as quanta of electromagnetic radiation provided an explanation.

In this specific case, a metal was exposed to photons at a frequency of 1.05×1015 s-1. The maximum kinetic energy of the emitted electrons was 3.80×10-19 J. The relationship between the photon energy (hf) and the binding energy (BE) of the electron determines the maximum kinetic energy of the ejected electrons.

Answer 2

The work function of the metal is 3.13 *
`10^{-19` J

The work function is commonly expressed in electron volts (eV) or joules (J) and depends on the material's properties. Different materials have different work functions, and this parameter plays a crucial role in understanding phenomena like the photoelectric effect and electron emission from surfaces.

The energy of the photon is

E = hf

E = 6.6 *
`10^{-34` * 1.05 *
`10^{15`

= 6.93 *
`10^{-19` J

W = E - KE

W = 6.93 *
`10^{-19` -
`3.80* 10^{-19`

W = 3.13 *
`10^{-19` J

Missing parts;

When a metal was exposed to photons at a frequency of 1.05×1015 s−1, electrons were emitted with a maximum kinetic energy of 3.80×10−19 J.

Calculate the work function, Φ, of this metal.