Question

Determine the equation of straight line passing through (-2;5)and parallel to the line x+2y-6=0​

Answer 1

y = (-1/2)x + 4

Explanation:

y = (-1/2)x + 4

slope : -1/2

(-2,5)

y - y1 = m(x - x1)

y - 5 = (-1/2)(x - (-2))

y - 5 = (-1/2)(x + 2)

y - 5 = (-1/2)x - 1

y = (-1/2)x + 4