Question

CHEM HELP PLEASE:

In a 6.431E1 g sample of NaHCO3, how many grams of sodium are present? Use two decimal places in atomic masses. Only give the numeric value of your answer. Don’t include the units.

Answer 1

1.76 grams of sodium (Na)

Step-by-step explanation:

Step-by-step calculation

To calculate the grams of sodium (Na) present in a sample of NaHCO3, we need to consider the molar mass ratio between Na and NaHCO3.

The molar mass of NaHCO3 is calculated as follows:

Na: 22.99 g/mol

H: 1.01 g/mol

C: 12.01 g/mol

O: 16.00 g/mol (three oxygen atoms in NaHCO3)

Molar mass of NaHCO3 = 22.99 g/mol + 1.01 g/mol + 12.01 g/mol + (16.00 g/mol × 3) = 84.01 g/mol

Next, we can calculate the grams of sodium (Na) present in the sample:

grams of Na = (molar mass of Na / molar mass of NaHCO3) × mass of NaHCO3

grams of Na = (22.99 g/mol / 84.01 g/mol) × 6.431E1 g

Calculating this expression:

grams of Na = (0.274 g/mol) × 6.431E1 g = 1.76 g

Summary

Therefore, there are 1.76 grams of sodium (Na) present in the 6.431E1 g sample of NaHCO3.