Question

Calculate the value of C₂ in the RC -filter circuit in Fig 2.4 (c) if the following values are known: f=50 Hz before full-wave rectification, V (ms) =0,8 V, Vr(ms) = 1,8 V and R = 20 ohms.​

Answer 1

Answer: C₂=1.59

Step-by-step explanation:

C₂ = (Vr(ms) - V(ms)) / (2πfR)

Given values:

f = 50 Hz

V(ms) = 0.8 V

Vr(ms) = 1.8 V

R = 20 ohms

Plugging in these values into the formula, we get:

C₂ = (1.8 V - 0.8 V) / (2π * 50 Hz * 20 ohms)

C₂ = 1 V / (6.28 * 50 * 20) F

C₂ ≈ 1 V / 628 F

C₂ ≈ 1.59 μF (microfarads)

Therefore, the value of C₂ in the RC-filter circuit is approximately 1.59 μF.