Question

For each sequence, fine the first 4 terms and the 10th term. a) 12-n b) 5-2n

Answer 1

a).11,10,9,8.

b)3,1,-1,-3

solution

a).12-n

12-(1)=11

12-n

12-2=10

12-n

12-3=9

12-n

12-4=8

10th term

12-n

12-10=2

b).5-2n

5-2(1)=3

5-2n

5-2(2)=1

5-2n

5-2(3)=-1

5-2n

5-2(4)=-3

10th term

5-2n

5-2(10)=-15