a).11,10,9,8.
b)3,1,-1,-3
solution
a).12-n
12-(1)=11
12-n
12-2=10
12-3=9
12-4=8
10th term
12-10=2
b).5-2n
5-2(1)=3
5-2n
5-2(2)=1
5-2(3)=-1
5-2(4)=-3
5-2(10)=-15
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