Answer:
(1) - v(t) = 9.18t - 1.12
(2) - a(t) = 9.18 m/s²
Step-by-step explanation:
We are given the position function, y(t) = 4.59t² - 1.12t + 0.03. We are asked to determine the following:
- The velocity function
- The acceleration function

To find the velocity function simply take the derivative of the position function.
y'(t) = v(t) = 9.18t - 1.12
Using the graph we can find the object's initial velocity by pugging in t=0.220 s.
=> v(0.220) = 9.18(0.220) - 1.12
=> v(0.220) = 0.8996 m/s

To find the acceleration function either take two derivatives of the position function or one of the velocity function.
y''(t) = v'(t) = a(t) = 9.18 m/s²
Thus, the object is speeding up with constant acceleration.