Question

Gerald had scores of 83,85,93, and 87 on four exams in his algebra class. What score will he need on his fifth exam to have an overall of 88?

Answer 1

Answer: 92

Explanation:

To find out the score Gerald needs on his fifth exam to have an overall average of 88, we can use the formula for calculating the average:

Average = (Sum of all scores) / (Number of scores)

In this case, the average we want to achieve is 88. We have four exam scores already: 83, 85, 93, and 87. Let's denote the score on the fifth exam as x.

To find the average, we need to add up all the scores and divide by the total number of scores:

(83 + 85 + 93 + 87 + x) / 5 = 88

Now we can solve for x:

(348 + x) / 5 = 88

Multiply both sides of the equation by 5 to eliminate the fraction:

348 + x = 440

Subtract 348 from both sides of the equation:

x = 440 - 348

x = 92

Therefore, Gerald will need to score 92 on his fifth exam to have an overall average of 88.

Answer 2

Explanation:

i guess that by "overall" they're referring

to the average score?

if that's the case, then the average of the five exams must be 88

average score = (exam1+exam2+exam3+exam4+exam5)/5

88 = (83+85+93+87+exam5)/5

88×5=348+exam5

440-348=exam5

92=exam5