Question

I really need help with this Arithmetic sequence question! anyone who can help me! I BLESS YOU ABUNDANTLY! ​

Answer 1

`t_(11)=29\\t_(15)=49\\\\t_n=t_1+(n-1)d\\\\29=t_1+(11-1)d\\49=t_1+(15-1)d\\\\t_1+10d=29\\t_1+14d=49`

Subtracting the first equation from the second one, we get:

`4d=20\\d=5`

`t_1+10\cdot5=29\\t_1=29-50\\t_1=-21`

Therefore

`t_1=-21\\t_2=-21+5=-16\\t_3=-16+5=-11\\t_4=-11+5=-6`