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A note of frequency 300 Hz is produced when the length of a wire is 80 cm and the tension is 40 N. What is the frequency if the length of the wire is halved and the tension is doubled?​

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The frequency of a note produced by a vibrating wire depends on various factors, including the length of the wire and the tension applied to it. We can use the formula for the fundamental frequency of a vibrating wire:

f = (1/2L) * sqrt(T/μ) ,

Where:

f = frequency

L = length of the wire

T = tension applied to the wire

μ = linear mass density of the wire

Let's calculate the initial linear mass density (μ) using the given information:

Length (L) = 80 cm = 0.8 m

Tension (T) = 40 N

Next, we'll find the initial frequency (f1) using the formula:

f1 = (1/2L) * sqrt(T/μ)

Now, we'll calculate the new length and tension:

New Length (L2) = 0.8 m / 2 = 0.4 m (halved)

New Tension (T2) = 40 N * 2 = 80 N (doubled)

Finally, we can find the new frequency (f2) using the same formula:

f2 = (1/2L2) * sqrt(T2/μ)

Comparing the initial frequency (f1) and the new frequency (f2) will allow us to determine the change in frequency.

User Tomasz Brzezina
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