Question

In a beaker containing 20 g of copper(II) oxide, 0.2 L of H₂SO, 2M? a. Write the equation for the reaction that occurs and indicate whether the amounts of both reagents react completely. If not, which one is excessive and to what extent? b. Calculate the amount of CuSO formed by this reaction.​

Answer 1

Use this format

Step-by-step explanation:

solution:-

CuO+H2 SO4⟶CuSo4 +H2O

Mol. wt. of CuO=79g

Mol. wt. of CuSO4 =159g

Mass of copper(II) sulfate formed when 79 gm of copper(II) oxide react =159g

Mass of copper(II) sulfate formed when 2.5 gm of copper(II) oxide react =

79

159×2.5=5.031g

Hence, 5.031 gm of CuSO4 formed when 2.5 gm of CuO reacts with excess H2SO4

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