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Consider the arithmetic sequence 21, 30, 39, 48, … and determine the number of terms that lie between

390 and the 29th term.​

2 Answers

6 votes

Answer:

The numbers are 282,291,300,309,318,327,336,345,354,363,372,381,

Common rhg
t(29) = 21 + (29 - 1)9


= 21 + (28)9

=21+252

=273

The numbers are 282,291,300,309,318,327,336,345,354,363,372,381

User Maziyar Mk
by
9.0k points
4 votes

Answer:

first add 390 to 29 then, divided it to the sequence and there's your answer

User Sajattack
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