225k views
0 votes
Solve the equation: 12x^2-13x+4=13x^2-5x+1

User Romuloux
by
7.7k points

2 Answers

7 votes

Answer:


x = -4 +√(19) = 0.36 \\\\or\\\\x=-4 -√(19) =-8.36

Explanation:


12x^2-13x+4=13x^2-5x+1\\\\\implies 12x^2-13x+4-13x^2+5x-1 = 0\\\\\implies -x^2-8x+3= 0\\\\\implies x^2+8x-3= 0\\

This is of the form ax² + bx + c = 0

Where a = 1, b = 8 and c = -3

Using the quadratic formula:


x=(-b\pm√(b^2 - 4ac) )/(2a)

we have:


x=(-8\pm√(8^2 - 4(-3)) )/(2)\\\\= (-8\pm√(64 + 12) )/(2)\\\\= (-8\pm√(76) )/(2)\\\\= (-8\pm2√(19) )/(2)\\\\= -4\pm√(19)


x = -4 +√(19) \;\;\;or\;\;\; x = -4 -√(19)\\\\x = -4 +4.36 \;\;\;or\;\;\; x = -4 -4.36\\\\x = 0.36 \;\;\;or\;\;\; x=-8.36

User Jgasiorowski
by
8.0k points
4 votes

Answer:

Explanation:

12x^2-13x+4=13x^2-5x+1

by solving it we get

x^2 + 8x - 3 =0

by quadratic formula

x=(-8+-
√(64+12))/2

x= -4+-
\sqrt{66\\/2

User Golly
by
8.5k points

No related questions found