Answer:
To find a and minus one a, we need to factorize the equation -2a^2 - a + 1 = 0.
First, we can simplify the equation by multiplying both sides by -1, so we have:
2a^2 + a - 1 = 0
Next, we can use the quadratic formula to solve for a:
a = (-b ± √(b^2 - 4ac)) / 2a
Plugging in the values for our equation, we have:
a = (-1 ± √(1^2 - 4(2)(-1))) / 2(2)
Simplifying this equation, we get:
a = (-1 ± √9) / 4
a = (-1 ± 3) / 4 Therefore, we get two possible values for a: a = -1/2 or a = 1/2
Now, we can use these values to find minus one a: If a = -1/2, then minus one a = -2/2 = -1 If a = 1/2,
then minus one a = 3/2 = 1Therefore, a can't be either -1/2 or 1/2.
Explanation:
To find a and minus one a, we need to factorize the equation -2a^2 - a + 1 = 0.
First, we can simplify the equation by multiplying both sides by -1, so we have:
2a^2 + a - 1 = 0
Next, we can use the quadratic formula to solve for a:
a = (-b ± √(b^2 - 4ac)) / 2a
Plugging in the values for our equation, we have:
a = (-1 ± √(1^2 - 4(2)(-1))) / 2(2)
Simplifying this equation, we get:
a = (-1 ± √9) / 4
a = (-1 ± 3) / 4 Therefore, we get two possible values for a: a = -1/2 or a = 1/2
Now, we can use these values to find minus one a: If a = -1/2, then minus one a = -2/2 = -1 If a = 1/2,
then minus one a = 3/2 = 1Therefore, a can't be either -1/2 or 1/2.