Question

A die with sides numbered 1 to 6 is rolled. Find the probability of rolling each outcome.

P(5)=
P(1 or 2)=
P(odd number)=
P(not 6)=
P(even number)=
P(1,2,3, or 4)=

PLEASE HELP IM LIKE IN A RUSHHH TYSM IF U ANSWER QUICKLY

Answer 1

Sure, I can help you quickly! Let's calculate the probabilities:

P(5) = 1/6 (since there is only one side with the number 5, and there are six equally likely outcomes)

P(1 or 2) = P(1) + P(2) = 1/6 + 1/6 = 2/6 = 1/3 (since there are two sides with the numbers 1 and 2)

P(odd number) = P(1) + P(3) + P(5) = 1/6 + 1/6 + 1/6 = 3/6 = 1/2 (since there are three odd numbers: 1, 3, and 5)

P(not 6) = 1 - P(6) = 1 - 1/6 = 5/6 (since there are five sides that are not 6)

P(even number) = 1 - P(odd number) = 1 - 1/2 = 1/2 (since there are three odd numbers and three even numbers)

P(1, 2, 3, or 4) = P(1) + P(2) + P(3) + P(4) = 1/6 + 1/6 + 1/6 + 1/6 = 4/6 = 2/3 (since there are four sides with the numbers 1, 2, 3, and 4)

I hope this helps! Let me know if you have any further questions.

Answer 2

Explanation:

Probability is the ratio of number of success/ total outcomes

So let calculate each probability

We have six total outcomes here in each scenario.

P(5)=1/6

P(1 or 2)=2/6=1/3

P(odd number )=3/6=1/2

P(not 6)= 5/6

Also

P(not 6)=1-P(6)=5/6

P(even number)=3/6=1/2

P(1,2,3,4)=4/6=2/3