Answer:
The magnitude of the normal force is equal to the weight of the box multiplied by the cosine of the angle θ.
Step-by-step explanation:
When a box is pulled along a frictionless surface at an angle θ, the normal force acting on the box is perpendicular to the surface and opposes the force of gravity.
In this case, the box is accelerating to the right, which means the force F is greater than the force of gravity pulling the box downward.
The magnitude of the normal force (N) can be determined by breaking down the forces in the vertical direction:
Sum of vertical forces = 0
N - mg * cos(θ) = 0
Here, mg * cos(θ) represents the vertical component of the weight of the box, which is balanced by the normal force.
Rearranging the equation, we have:
N = mg * cos(θ)