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How do you solve this by elimination?
{2x - 3y = 14
{2x + y = -10

User Obafemi
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2 Answers

4 votes

Refer to Attachment ^-^

How do you solve this by elimination? {2x - 3y = 14 {2x + y = -10-example-1
User MatlabSorter
by
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6 votes

The answer is:

(-2, -6)

Work/explanation:

We need to subtract the two equations:


\begin{cases}\sf{2x-3y=14}\\\sf{2x+y=-10}\end{cases}


\sf{2x-2x-3y-y=14-(-10)}


\sf{-4y=14+10}


\sf{-4y=24}

Divide each side by -4:


\sf{y=-6}

Now plug the solution for y, which is -6, into any equation:

2x + (-6) = -10

2x - 6 = -10

2x = -10 + 6

2x = -4

x = -2

Hence, the answer to the system is (-2, -6).

User Arun Raaj
by
7.8k points

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