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B. A man shared 600 cows among his daughters in the ratio 3:5:4 respectively.

I. How much did each get?
ii. How many did the first two_ daughters get all together? 3marks​

1 Answer

6 votes

Explanation:

To solve the problem, let's first calculate the number of cows each daughter received.

Given:

Total number of cows = 600

Ratio of cows distributed: 3:5:4 (for the three daughters)

I. How much did each daughter get?

To find out how much each daughter received, we need to calculate their shares based on the given ratio.

Let's denote the share of the first daughter as 3x, the share of the second daughter as 5x, and the share of the third daughter as 4x.

The sum of the shares should equal the total number of cows:

3x + 5x + 4x = 600

12x = 600

x = 600 / 12

x = 50

Now we can find the individual shares for each daughter:

First daughter: 3x = 3 * 50 = 150 cows

Second daughter: 5x = 5 * 50 = 250 cows

Third daughter: 4x = 4 * 50 = 200 cows

So, each daughter received the following number of cows:

- First daughter: 150 cows

- Second daughter: 250 cows

- Third daughter: 200 cows

II. How many cows did the first two daughters get all together?

To find the total number of cows received by the first two daughters, we add up their individual shares:

Total = Share of first daughter + Share of second daughter

Total = 150 cows + 250 cows

Total = 400 cows

Therefore, the first two daughters received a total of 400 cows together.

I hope this helps! Let me know if you have any further questions.

User Nikolaj Simonsen
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