To find the other zeros of the function f(x) = x^4 - 21x^2 - 100 given that -2i is a zero, we can use the conjugate zero theorem.
Since -2i is a zero, its conjugate 2i will also be a zero of the function.
Now we can use polynomial long division or synthetic division to find the quadratic expression that results from dividing f(x) by (x + 2i)(x - 2i).
Performing the division, we get:
(x^4 - 21x^2 - 100) / ((x + 2i)(x - 2i)) = x^2 - 5
So the other two zeros of f(x) are the solutions to the equation x^2 - 5 = 0.
Solving this equation, we find two additional zeros: x = √5 and x = -√5.
Therefore, the zeros of the function f(x) = x^4 - 21x^2 - 100 are -2i, 2i, √5, and -√5.