Question

What is the pH of a solution with [H+] = 1.25 x 10^-10M?

Answer 1

9.90

Step-by-step explanation:

Given [H+] = 1.25 x 10^-10 M, we can calculate the pH using the formula:

pH = -log10([H+])

pH = -log10(1.25 x 10^-10)

Using logarithmic properties:

pH = -log10(1.25) - log10(10^-10)

Since log10(10^-10) is equal to -10:

pH = -log10(1.25) - (-10)

pH = -log10(1.25) + 10

Now, evaluating the logarithm using a calculator:

pH = -0.0969 + 10

pH = 9.9031

Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately 9.9031. Rounding it to two decimal places, the pH is approximately 9.90.

Answer 2

The pH of a solution is calculated using the equation:

pH = -log[H+]

Given [H+] = 1.25 x 10^-10 M:

pH = -log(1.25 x 10^-10)
pH = -log(1.25) + log(10^-10)
pH ≈ -9 + (-10)
pH ≈ -19

Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately -19.