Question

M∠SQR = (2x + 6)° and m∠PQR = (10x - 5)° and m∠SQP = 61°. Find m∠SQR and m∠PQR.

Answer 1

See below for answers

Explanation:

There's no diagram, but it looks like these angles are supplementary, meaning their sum is 180°. Therefore, we must find x first, and then plug it into angles SQR and PQR:

`2x+6+10x-5+61=180\\12x+62=180\\12x=118\\x\approx9.83`

Therefore:

`m\angle SQR = (2\cdot9.83+6)^\circ\approx25.7^\circ\\m\angle PQR = (10\cdot9.83-5)^\circ=93.3^\circ`