Question

A ball is released from the bottom of an elevator which is travelling upward with a velocity of 6 ft/s. If the ball strikes the bottom of the elevator shaft in 3 s. Determine the height of the elevator from the bottom of the shaft at the instant the ball is released

Answer 1

Step-by-step explanation:

df = do + vot + 1/2 at ^2 do = what you are looking for df = ground = 0

0 = do + 6 (3 ) + 1/2 ( -9.81) (3^2)

do = 26.1 m