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The table shows how many children and adults prefer each of two different fruits. How would you find the joint relative frequency of being an adult who prefers watermelon?%0D%0A%0D%0AWatermelon%09Grapes%09Total%0D%0AChild%09132%0985%09217%0D%0AAdult%09111%09117%09228%0D%0ATotal%09243%09202%09445%0D%0A%0D%0AA.%0D%0ADivide 111 by 228.%0D%0A%0D%0AB.%0D%0ADivide 111 by 243.%0D%0A%0D%0AC.%0D%0ADivide 111 by 445.%0D%0A%0D%0AD.%0D%0ADivide 243 by 445.

User Astra
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The joint relative frequency is calculated by dividing the frequency of a specific subset (in this case, the number of adults who prefer watermelon) by the total number of data points.

Here, the specific subset is adults who prefer watermelon, which is 111. The total number of data points is the sum of all children and adults, regardless of fruit preference, which is 445.

So, to find the joint relative frequency of being an adult who prefers watermelon, you would divide 111 by 445.

Hence, the correct answer is:

C. Divide 111 by 445.

User Rahul Mankar
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The joint relative frequency of being a child who prefers watermelon is 132/445 option (A) Divide 132 by 445 is correct.

It is defined as the frequency that can be evaluated by the two-way frequency table.

Usually, we can obtain this frequency by dividing the frequency that is not in the frequency cell by the total frequency.

To find the joint relative frequency of being a child who prefers watermelon:

Total number of children who prefers watermelon = 132

Total number of children and adults = 445

joint relative frequency of being a child who prefers watermelon:

= 132/445

Thus, the joint relative frequency of being a child who prefers watermelon is 132/445 option (A) Divide 132 by 445 is correct.

The table shows how many children and adults prefer each of two different fruits. How-example-1
User Nibir
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