Answer:




Explanation:
In order to solve for the solution set of a quadratic equation, we can use the quadratic formula:

where a, b, and c are the coefficients of the quadratic equation.
For 2x^2-8x+5=0
Comparing the above equation with ax^2+bx+c
In this case, the coefficients are:
a = 2
b = -8
c = 5
Plugging these values into the quadratic formula, we get:





For 2x^2-10x-3=0
Comparing the above equation with ax^2+bx+c
n this case, the coefficients are:
a = 2
b = -10
c = -3
Plugging these values into the quadratic formula, we get:



For 2x^2-8x-3=0
Comparing the above equation with ax^2+bx+c
n this case, the coefficients are:
a = 2
b = -8
c = -3
Plugging these values into the quadratic formula, we get:




For 2x^2-9x-1=0
Comparing the above equation with ax^2+bx+c
n this case, the coefficients are:
a = 2
b=-9
c = -1
Plugging these values into the quadratic formula, we get:



For 2x^2-9x+6=0
n this case, the coefficients are:
a = 2
b = -9
c = -6
Plugging these values into the quadratic formula, we get:

