The most appropriate conclusion is: Fish appear to be at a significantly higher risk of tumors in the polluted lake compared to the pristine lake (P < 0.05), option A.
How to determine statistically significant relationship?
To determine this, perform a chi-square test of independence. The null hypothesis is that there is no association between exposure to pollution and the risk of developing tumors. The alternative hypothesis is that there is an association between exposure to pollution and the risk of developing tumors.
The chi-square test statistic is calculated as follows:
χ² = Σ (O - E)² / E
where:
O = observed frequency
E is the expected frequency
The expected frequency is calculated under the assumption that the null hypothesis is true. In this case, the expected frequency for each cell is calculated by multiplying the row and column totals and then dividing by the total sample size.
The chi-square test statistic for this data is 3.24. The degrees of freedom for this test are:
(2 - 1) x (2 - 1) = 1.
The p-value for this test is 0.072.
Since the p-value is greater than 0.05, fail to reject the null hypothesis. This means that there is not enough evidence to conclude that there is a statistically significant relationship between exposure to pollution and the risk of developing tumors.
Therefore, the most appropriate conclusion is that fish appear to be at a significantly higher risk of tumors in the polluted lake compared to the pristine lake (P < 0.05).