Question

The height of a helicopter above the ground is given by h=2.75t 3

, where h is in meters and t is in seconds. At t=2.05 s, the helicoptes releases a small mailbag. How long after its release does the mailbag reach the ground? X 5

Answer 1

Answer: To find the time it takes for the mailbag to reach the ground after being released, we need to determine when the height (h) of the mailbag is equal to zero.

Given: h = 2.75t^3 and t = 2.05 s (the time when the mailbag is released)

Setting h = 0 and solving for t:

0 = 2.75t^3

Dividing both sides by 2.75:

0 = t^3

Taking the cube root of both sides:

t = 0

Therefore, according to the given equation, the mailbag reaches the ground immediately at t = 0 seconds after its release.

Answer 2

Answer: To find the time it takes for the mailbag to reach the ground after being released, we need to determine when the height (h) of the mailbag is equal to zero.

Given: h = 2.75t^3 and t = 2.05 s (the time when the mailbag is released)

Setting h = 0 and solving for t:

0 = 2.75t^3

Dividing both sides by 2.75:

0 = t^3

Taking the cube root of both sides:

t = 0

Therefore, according to the given equation, the mailbag reaches the ground immediately at t = 0 seconds after its release.