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How many sixteenths of an inch are there in 3 inches, 16 inches, and 7 inches? 17. A certain job requires the use of twelve metal strips 33/4 inches wide by 41/2 inches long. A piece of metal 4l/2 inches wide is found in the sheet metal rack. How long must this piece be in order to supply the twelve pieces needed for the job? Note: The pieces will be cut on the shears so no allowance need be made for cutting. 18. Five aluminum castings weigh 121/4lbs,1147/8lbs, 181/2lbs., 2563/4lbs. and 393/8lbs. What is the total weight of all five castings? 19. An aluminum bar has been turned on a lathe to finished diameter of 37/8 inches. If a cut 5/16 inch deep was taken on the lathe what was the orginal diameter of the bar? 20. A bar of steel weighs 384/5 lbs. Two pieces each weighing 13/8lbs. are cut from the bar. What is the weight of the remainder of the bar?

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16. To convert inches to sixteenths of an inch, we multiply the given inches by 16.

a) 3 inches * 16 = 48 sixteenths of an inch.
b) 16 inches * 16 = 256 sixteenths of an inch.
c) 7 inches * 16 = 112 sixteenths of an inch.

Therefore, there are 48 sixteenths of an inch in 3 inches, 256 sixteenths of an inch in 16 inches, and 112 sixteenths of an inch in 7 inches.

17. The metal strips required for the job are 3/4 inches wide and 4 1/2 inches long. If a piece of metal in the rack is 4 1/2 inches wide, we need to determine the length required to supply the twelve pieces.

Length of each piece = 4 1/2 inches

Total length required for twelve pieces = Length of each piece * Number of pieces
Total length required for twelve pieces = (4 1/2 inches) * 12
Total length required for twelve pieces = 54 inches

Therefore, the piece of metal must be at least 54 inches long to supply the twelve pieces needed for the job.

18. To find the total weight of the five aluminum castings, we can add up the weights of each casting.

Total weight = 121/4 lbs + 1147/8 lbs + 181/2 lbs + 2563/4 lbs + 393/8 lbs

To add fractions with different denominators, we need to find a common denominator. In this case, the common denominator is 8.

Total weight = (121/4 + 1147/8 + 181/2 + 2563/4 + 393/8) lbs

Simplifying and adding the fractions, we have:

Total weight = 484/16 + 1376/16 + 576/16 + 2050/16 + 3152/16 lbs
Total weight = 9640/16 lbs

Since 9640/16 can be simplified, we have:

Total weight = 602.5 lbs

Therefore, the total weight of all five castings is 602.5 lbs.

19. The aluminum bar has been turned on a lathe to a finished diameter of 3 7/8 inches. If a cut 5/16 inch deep was taken on the lathe, we need to determine the original diameter of the bar.

Original diameter = Finished diameter + 2 * Depth of cut
Original diameter = 3 7/8 inches + 2 * 5/16 inch

Calculating the expression, we have:

Original diameter = 3 7/8 inches + 10/16 inch
Original diameter = 3 7/8 inches + 5/8 inch
Original diameter = 3 7/8 inches + 5/8 inch
Original diameter = 4 1/2 inches

Therefore, the original diameter of the bar was 4 1/2 inches.

20. The bar of steel weighs 384/5 lbs. Two pieces weighing 13/8 lbs each are cut from the bar. We need to determine the weight of the remainder of the bar.

Weight of the remainder = Total weight - Weight of the two cut pieces
Weight of the remainder = 384/5 lbs - 13/8 lbs - 13/8 lbs

Calculating the expression, we have:

Weight of the remainder = 384/5 lbs - 26/8 lbs
Weight of the remainder = 384/5 lbs - 13/
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