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Use factoring to solve the equation. b^(2)+13b+36=0

User Gwell
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1 Answer

1 vote

Answer:

b = -9; b = -4

Explanation:

b^2 + 13b + 36 is in standard form, whose general equation is:

ax^2 + bx + c = 0.

Thus, 1 = a, 13 = b, and 36 = c.

To solve by factoring, we want to find two terms whose product equals a * c and whose sum equals b. Thus, we should list the factors of 1 and 36:

1 * 36 = 36

2 * 18 = 36

3 * 12 = 36

4 * 9 = 36

6 * 6 = 36

9 * 4 = 36 and 9 + 4 = 13

Thus, we have:

(b + 9)(b + 4) = 0

Now we set each term equal to 0 and solve for b:

Setting b + 9 equal to 0:

b + 9 = 0

b = -9

Setting b + 4 equal to 0:

b + 4 = 0

b = -4

Thus, the solutions to b^2 + 13b + 36 = 0 are b = -9 and b = -4.

User Baraka
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